Coordinate Representation Math Example 4

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Example 4

hard
Three vertices of a parallelogram are A(1,2)A(1,2), B(5,2)B(5,2), C(7,6)C(7,6). Using coordinate methods, find the fourth vertex DD and compute the area of the parallelogram.

Solution

  1. 1
    Step 1: In parallelogram ABCDABCD, ABโ†’=DCโ†’\overrightarrow{AB} = \overrightarrow{DC}. ABโ†’=(4,0)\overrightarrow{AB} = (4,0), so D=Cโˆ’(4,0)=(3,6)D = C - (4,0) = (3, 6).
  2. 2
    Step 2: Base โˆฃABโˆฃ=4|AB| = 4. Height == vertical distance from ABAB (along y=2y=2) to CC or DD: โˆฃ6โˆ’2โˆฃ=4|6-2| = 4.
  3. 3
    Step 3: Area =baseร—height=4ร—4=16= \text{base} \times \text{height} = 4 \times 4 = 16 square units.

Answer

D(3,6)D(3, 6); area =16= 16 square units.
Coordinate geometry makes abstract geometric relationships computational. The fourth vertex is found using vector addition, and the area is computed from base and height read from the coordinates.

About Coordinate Representation

Describing geometric objects precisely using ordered pairs (x,y)(x, y) or triples (x,y,z)(x, y, z) in a coordinate system.

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