Coordinate Proofs Math Example 2

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Example 2

hard
Use a coordinate proof to show that the midpoints of the sides of any quadrilateral form a parallelogram (Varignon's Theorem).

Solution

  1. 1
    Step 1: Let the quadrilateral have vertices A(x1,y1)A(x_1,y_1), B(x2,y2)B(x_2,y_2), C(x3,y3)C(x_3,y_3), D(x4,y4)D(x_4,y_4) in order.
  2. 2
    Step 2: Find the midpoints of each side: MAB=(x1+x22,y1+y22)M_{AB} = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right), MBC=(x2+x32,y2+y32)M_{BC} = \left(\frac{x_2+x_3}{2}, \frac{y_2+y_3}{2}\right), MCD=(x3+x42,y3+y42)M_{CD} = \left(\frac{x_3+x_4}{2}, \frac{y_3+y_4}{2}\right), MDA=(x4+x12,y4+y12)M_{DA} = \left(\frac{x_4+x_1}{2}, \frac{y_4+y_1}{2}\right).
  3. 3
    Step 3: Compute the midpoint of diagonal MABMCDM_{AB}M_{CD}: (x1+x22+x3+x422,y1+y22+y3+y422)=(x1+x2+x3+x44,y1+y2+y3+y44)\left(\frac{\frac{x_1+x_2}{2}+\frac{x_3+x_4}{2}}{2}, \frac{\frac{y_1+y_2}{2}+\frac{y_3+y_4}{2}}{2}\right) = \left(\frac{x_1+x_2+x_3+x_4}{4}, \frac{y_1+y_2+y_3+y_4}{4}\right).
  4. 4
    Step 4: Compute the midpoint of diagonal MBCMDAM_{BC}M_{DA}: the same result (x1+x2+x3+x44,y1+y2+y3+y44)\left(\frac{x_1+x_2+x_3+x_4}{4}, \frac{y_1+y_2+y_3+y_4}{4}\right).
  5. 5
    Step 5: Since the diagonals of quadrilateral MABMBCMCDMDAM_{AB}M_{BC}M_{CD}M_{DA} bisect each other, it is a parallelogram. โ– \blacksquare

Answer

The midpoint quadrilateral has diagonals that bisect each other, so it is a parallelogram.
A quadrilateral is a parallelogram if and only if its diagonals bisect each other. By showing both diagonals of the midpoint quadrilateral share the same midpoint (the average of all four original vertices), we prove it is a parallelogram for any quadrilateral.

About Coordinate Proofs

A method of proving geometric properties by placing figures on a coordinate plane and using algebraic formulas (distance, midpoint, slope) to verify relationships.

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