Conic Sections Overview Math Example 4

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Example 4

hard
The general equation 2x2+2y2+Bxy8=02x^2 + 2y^2 + Bxy - 8 = 0 represents a circle only when BB takes a specific value. Find that value.

Solution

  1. 1
    A circle requires no xyxy term (i.e., B=0B = 0) and equal coefficients on x2x^2 and y2y^2 (already satisfied: both are 22).
  2. 2
    So B=0B = 0. The equation becomes 2x2+2y2=82x^2 + 2y^2 = 8, or x2+y2=4x^2 + y^2 = 4, a circle of radius 22.

Answer

B=0B = 0
For a second-degree equation to represent a circle, three conditions must hold: the coefficients of x2x^2 and y2y^2 must be equal and have the same sign, and the coefficient of xyxy must be zero. Any nonzero xyxy term would rotate the axes, producing an ellipse or hyperbola instead.

About Conic Sections Overview

The four curves—circle, ellipse, parabola, and hyperbola—obtained by slicing a double cone with a plane at different angles.

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