Amplitude Math Example 3

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Example 3

medium
A sinusoidal function has a maximum value of 88 and a minimum value of 22. Find the amplitude and midline.

Solution

  1. 1
    Amplitude =maxโˆ’min2=8โˆ’22=3= \frac{\text{max} - \text{min}}{2} = \frac{8 - 2}{2} = 3.
  2. 2
    Midline =max+min2=8+22=5= \frac{\text{max} + \text{min}}{2} = \frac{8 + 2}{2} = 5, so y=5y = 5.

Answer

Amplitude=3,Midline:ย y=5\text{Amplitude} = 3, \quad \text{Midline: } y = 5
When given the maximum and minimum values of a sinusoidal function, the amplitude is half the total vertical range and the midline is the average of the extreme values. This allows you to determine AA and DD in y=Asinโก(Bx+C)+Dy = A\sin(Bx+C) + D.

About Amplitude

Amplitude is the maximum vertical distance from the midline of a periodic function to a peak or trough.

Learn more about Amplitude โ†’

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