Practice Theoretical Yield in Chemistry

Use these practice problems to test your method after reviewing the concept explanation and worked examples.

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Quick Recap

The maximum amount of product that could be formed in a chemical reaction, calculated from the stoichiometry of the balanced equation using the limiting reactant.

The perfect-world result — the most product you could possibly get if nothing is lost or wasted.

Showing a random 20 of 50 problems.

Example 1

medium
Compute the theoretical yield of NaCl (in g) when 2 mol Na reacts with 0.5 mol Cl2 via 2Na+Cl2→2NaCl. (MNaCl=58.5)

Example 2

hard
In Fe2O3+3CO→2Fe+3CO2, theoretical yield (g) of Fe from 160 g Fe2O3 (M=160) with excess CO. (MFe=56)

Example 3

medium
In CaCO3→CaO+CO2, theoretical yield (g) of CaO from 100 g CaCO3? (MCaCO3=100, MCaO=56)

Example 4

easy
What is the theoretical yield?

Example 5

challenge
In C+O2→CO2 with 6 g C (M=12) and 8 g O2 (M=32), find theoretical yield of CO2 (g). (M=44)

Example 6

easy
In 2H2+O2→2H2O, theoretical yield (mol) of H2O from 4 mol H2 (excess O2)?

Example 7

hard
Theoretical yield of a reaction is 25.0 g and actual yield is 18.0 g. Percent yield?

Example 8

easy
In N2+3H2→2NH3, theoretical yield (g) of NH3 from 1 mol N2 (excess H2)? (MNH3=17)

Example 9

easy
In C+O2→CO2, what is the theoretical yield (mol) of CO2 from 2 mol C?

Example 10

medium
Calculate the theoretical yield of water when 8.0 g of hydrogen reacts with excess oxygen. (2H2+O2→2H2O; H = 1.008, O = 16.00 g/mol)

Example 11

easy
Define theoretical yield and explain how it differs from actual yield.

Example 12

medium
In 2H2+O2→2H2O with 4 g H2 (M=2) and excess O2, theoretical yield of water (g)? (M=18)

Example 13

easy
In N2+3H2→2NH3, theoretical yield (mol) of NH3 from 2 mol N2 (excess H2)?

Example 14

easy
In 2Mg+O2→2MgO, theoretical yield (g) of MgO from 1 mol Mg (excess O2)? (MMgO=40)

Example 15

easy
In 2KClO3→2KCl+3O2, theoretical yield (mol) of O2 from 2 mol KClO3?

Example 16

hard
A student reacts 6.50 g of zinc with 20.0 mL of 3.00 M HCl. The reaction is Zn+2HCl→ZnCl2+H2. Determine the limiting reactant and the theoretical yield of ZnCl2. (Zn = 65.38, ZnCl2 = 136.28 g/mol)

Example 17

easy
In C+O2→CO2, what is the theoretical yield (mol) of CO2 from 5 mol of C (excess O2)?

Example 18

hard
In 2Al+3Cl2→2AlCl3, theoretical yield (g) of AlCl3 from 5.4 g Al (M=27) and 21.3 g Cl2 (M=71)? (MAlCl3=133.5)

Example 19

easy
The theoretical yield is computed from the ____ reactant.

Example 20

hard
In CH4+2O2→CO2+2H2O, theoretical yield (g) of CO2 from 8 g CH4 (M=16, excess O2)? (MCO2=44)
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