Percent Composition Chemistry Example 1

Follow the full solution, then compare it with the other examples linked below.

Example 1

easy
Calculate the percent composition by mass of each element in H2O\text{H}_2\text{O}.

Solution

  1. 1
    Molar mass of H2O=2(1.008)+16.00=18.02โ€‰g/mol\text{H}_2\text{O} = 2(1.008) + 16.00 = 18.02\,\text{g/mol}.
  2. 2
    %H =2(1.008)18.02ร—100%=2.01618.02ร—100%=11.19%= \frac{2(1.008)}{18.02} \times 100\% = \frac{2.016}{18.02} \times 100\% = 11.19\%.
  3. 3
    %O =16.0018.02ร—100%=88.81%= \frac{16.00}{18.02} \times 100\% = 88.81\%.

Answer

H:ย 11.19%,O:ย 88.81%\text{H: } 11.19\%,\quad \text{O: } 88.81\%
Percent composition tells us the mass fraction of each element in a compound. The percentages must add up to 100% (within rounding error).

About Percent Composition

Percent composition is the percentage by mass of each element in a chemical compound.

Learn more about Percent Composition โ†’

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