Oxidation Number Chemistry Example 4

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Example 4

hard
In the reaction Fe2O3+3COโ†’2Fe+3CO2\text{Fe}_2\text{O}_3 + 3\text{CO} \rightarrow 2\text{Fe} + 3\text{CO}_2, determine the oxidation number of iron and carbon on each side. Which element is oxidized and which is reduced?

Solution

  1. 1
    Left side: In Fe2O3\text{Fe}_2\text{O}_3, oxygen is โˆ’2-2, so Fe is +3+3. In CO\text{CO}, oxygen is โˆ’2-2, so C is +2+2.
  2. 2
    Right side: Fe is 00 (pure element). In CO2\text{CO}_2, oxygen is โˆ’2-2, so C is +4+4.
  3. 3
    Iron goes from +3+3 to 00 โ€” it gains electrons โ†’ reduced. Carbon goes from +2+2 to +4+4 โ€” it loses electrons โ†’ oxidized. CO is the reducing agent; Feโ‚‚Oโ‚ƒ is the oxidizing agent.

Answer

Fe:ย +3ย โ†’ย 0ย (reduced);ย C:ย +2ย โ†’ย +4ย (oxidized)\text{Fe: +3 โ†’ 0 (reduced); \quad C: +2 โ†’ +4 (oxidized)}
This is the blast furnace reaction for extracting iron from its ore. Tracking oxidation numbers reveals the electron transfer: CO donates electrons to Feยณโบ, reducing it to metallic iron.

About Oxidation Number

A number assigned to each atom in a compound using a set of rules, representing the hypothetical charge that atom would carry if all bonds.

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