Molecular Formula Chemistry Example 4

Follow the full solution, then compare it with the other examples linked below.

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A compound has empirical formula

\text{CH}

and molar mass

78\,\text{g/mol}

. Find the molecular formula. (C =

12.01

, H =

1.008

)

1
Empirical formula mass of CH $= 12.01 + 1.008 = 13.02\,\text{g/mol}$ .
2
Multiplier $= \frac{78}{13.02} = 5.99 \approx 6$ . Molecular formula $= \text{C}_6\text{H}_6$ (benzene).

Answer

\text{C}_6\text{H}_6\text{ (benzene)}

Benzene is a classic example where the empirical formula (CH) is much simpler than the molecular formula (

\text{C}_6\text{H}_6

). The molecular formula reveals the actual size of the molecule.

About Molecular Formula

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